The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
irrational i think
We are given pH values 3, 12, 2, 7, or 9.
We know that on the pH scale, 7 is neutral, less than 7 are acidic and greater than 7 are basic (alkaline).
As we go from greater to less numbers than 7, it becomes more and more acidic.
And if we go from greater and greater number than 7, it becomes more basic.
Now, we can conclude the given numbers and their nature on pH scale.
7 is neutral, 3 is acidic and 2 is stronger acidic than 3.
9 is basic and 12 is stronger basic than 9.