**Answer:**

<em>Mistake in question, if there were 25 heads, then there are</em>

<em>13 chickens, 5 cows, 7 horses</em>

**Step-by-step explanation:**

<u>System of Equations</u>

Let's call x=number of chickens, y=number of cows, z=number of horses

We know Jack has two more horses than cows, so

z=y+2

We also know there are 24 heads, one per animal, so

x+y+z=24

Combining with the previous condition:

x+y+y+2=24

x+2y=22

We finally know there are 74 feet, two for each chicken and four for each cow or horse:

2x+4y+4z=74

Combining with the first condition

2x+4y+4(y+2)=74

2x+4y+4y+8=74

2x+8y=66

Dividing by 2

x+4y=33

Let's bring the first equation here

x+2y=22

Subtracting both

2y=11

It would give us a decimal number of cows

y=5.5

And a decimal number of horses

z=7.5

And a integer number of chickens

x=22-11=11

If the number of heads would have been 25, our problem will be correctly stated and the answer would be

13 chickens, 5 cows, 7 horses