An automobile insurance company claims that teenage drivers save on average $490 per year when compared to the same coverage fro
m another company, with a standard deviation of $65 per year. Natalia is a teenager and a customer of this company and her average savings was $470 per year. What is the z-value for Natalia’s savings rounded to the nearest hundredth? Question 1 options:
The z-value is -0.90.
The z-value is 0.90
The z-value is 0.31.
The z-value is -0.31.