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Mashutka [201]
1 year ago
11

(1 point) Let f(x,y)=xex2−yf(x,y)=xex2−y and P=(6,36)P=(6,36). (a) Calculate ∥∇fP∥‖∇fP‖. (b) Find the rate of change of ff in th

e direction ∇fP∇fP. (c) Find the rate of change of ff in the direction of a vector making an angle of 45∘45∘ with ∇fP∇fP. Answers : (a) (b) (c)
Mathematics
1 answer:
IrinaK [193]1 year ago
6 0

Answer:

no

Step-by-step explanation:

norueueueueueueuieueeueur

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Musya8 [376]

Answer:

We get t= 7.22 and t=0.28

The correct options are Option A and Option G

Step-by-step explanation:

The height h of toy rocket at time t seconds after  launch is given by the equation h(t) = -16t^2 + 120t + 8

We need to find how many seconds  until the rocket is 40 feet?

We are given height of rocket h(t) = 40 feet

and we need to find time t

Using the equation h(t) = -16t^2 + 120t + 8 we can find time t

We have h(t)=40

h(t) = -16t^2 + 120t + 8\\Put\:h(t)=40\\40= -16t^2 + 120t + 8\\16t^2-120t-8+40=0\\16t^2-120t+32=0

Now, we will solve the quadratic equation using quadratic formula: t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

We have a =16, b=-120 and c=32

Putting values and finding t

t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\t=\frac{-(-120)\pm\sqrt{(-120)^2-4(16)(32)}}{2(16)}\\t=\frac{120\pm\sqrt{14400-2048}}{32}\\t=\frac{120\pm\sqrt{12352}}{32}\\t=\frac{120\pm111.12}{32}\\t=\frac{120+111.12}{32}, t=\frac{120-111.12}{32}\\t=7.22\:,\:t=0.28

So, we get t= 7.22 and t=0.28

The correct options are Option A and Option G

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1 year ago
What is the Fraction of the items are round
mario62 [17]
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4x + 5 + 3x – 12 =<br><br><br>A.9x-9<br><br>B.7x+7<br><br>C.7x-7<br><br><br>​
zalisa [80]

Answer:

7x - 7

Step-by-step explanation:

In this equation you are going to add like terms.

The like terms you have are the terms with x and then the terms without the x.

So 4x + 3x = 7x

5 - 12 = -7

So your answer is 7x-7

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1 year ago
What is the slope intercept form of m=1/2 and (-2,4)
sweet [91]

Answer:

y=1/2x+5

Step-by-step explanation:

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