The given sequence is
BHE : FLI : JPM
If is clear that, alphabets on first places are B, F, J. Difference between their place vales is 4.
B+4=F,F+4=J ; so alphabet on first place of next term of sequence is J+4=N.
Similarly, alphabets on second places are H, L, P. Difference between their place vales is 4.
H+4=L,L+4=P ; so alphabet on second place of next term of sequence is P+4=T.
Alphabets on third places are E, I, M. Difference between their place vales is 4.
E+4=I,I+4=M ; so alphabet on third place of next term of sequence is M+4=Q.
Therefore, the next term is NTQ.
Inlet velocity = Vin = 25 m/s
Exit velocity = Vout = 250 m/s
Exit Temperature = Tout = 300K
Exit Pressure = Pout = 100 kPa
Inlet Temperature of argon = ?
Inlet Temperature of helium = ?
Inlet Temperature of nitrogen = ?
Inlet Temperature of argon = 360K
Inlet Temperature of helium = 306K
Inlet Temperature of nitrogen = 330K
Recall that the energy equation is given by
Where Cp is the specific heat constant of the gas.
Re-arranging the equation for inlet temperature
For Argon Gas:
The specific heat constant of argon is given by (from ideal gas properties table)
So, the inlet temperature of argon is
For Helium Gas:
The specific heat constant of helium is given by (from ideal gas properties table)
So, the inlet temperature of helium is
For Nitrogen Gas:
The specific heat constant of nitrogen is given by (from ideal gas properties table)
So, the inlet temperature of nitrogen is
Note: Answers are rounded to the nearest whole numbers.
the minimum expected elastic modulus is 372.27 Gpa
First we put down the data in the given question;
Volume fraction = 0.84
Volume fraction of matrix material = 1 - 0.84 = 0.16
Elastic module of particle = 682 GPa
Elastic module of matrix material = 110 GPa
Now, the minimum expected elastic modulus will be;
= ( × ) / ( + )
so we substitute in our values
= (682 × 110 ) / ( [ 682 × 0.16 ] + [ 110 × 0.84] )
= ( 75,020 ) / ( 109.12 + 92.4 )
= 75,020 / 201.52
= 372.27 Gpa
Therefore, the minimum expected elastic modulus is 372.27 Gpa
Grade of road (G) = -0.58 •/•
Vd = 52mi/h = 83.868 Km/hr
Vd is approximately 84Km/hr
Let's take >>>>> D = d = 135m
Perception Reaction Time (PRT) = tp = 2.5 sec
To find grade of road (G), we have,
76.62 = 7056 / ( 90.622 - 2.54G )
6493.457 - 194.6148G = 7056
-112.542 = 194.61G
G = -112.542 / 194.6148 = -0.578 •/•
G = 0.578 = 0.58
For most uses you'll want your water heated to 120 F(49 C) In this example you'd need a demand water heater that produces a temperature rise and it will take about 2 hours
Since outlet temperature of cold liquid is greater than hot fluid outlet temperature therefore it is counter flow heat exchanger
Equating Heat exchange
we can see that heat capacity of hot fluid is minimum
Also from energy balance