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Ymorist [56]
1 year ago
11

The filament of an electric bulb draws a current of 0.4 ampere. Calculate the amount of charge flowing through the filament if t

he bulb glows for 2 hours. Also calculate the number of electrons passed.
Physics
1 answer:
Marina86 [1]1 year ago
3 0
Here I =0.4 amp and t=2hr or 2×60×60 sec
We known I=nQ/t where Q is charge and n is no of charge.
n=It/Q
0.4x(2x60x60)/1.6x10^-19
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The volume of the gas at 500^{\circ} \text{C} is \fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}.

Further Explanation:

Consider the pressure of the gas to be constant.  

The change in the volume of the gas when the temperature of the gas is varied by keeping the pressure of the gas at a constant value is defined by the Charles' Law.

Concept:

According to the Charles law, the volume of the gas is directly proportional to the temperature of the gas at constant pressure.

The Charles' law can be stated as:

\fbox{\begin\\V\propto T\\\end{minispace}}

The above expression can we written as.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Convert the temperature of the gas into kelvin.

T=273+T^\circ\text{C}}}

Here, T is the temperature in kelvin and T^\circ\text{C}}} is the temperature in centigrade.  

The initial temperature of the gas is 50^\circ\text{C}. The temperature of the gas in kelvin is.  

\begin{aligned}{T_1}&=273+50\\&=323\,{\text{K}}\\\end{aligned}

The final temperature of the gas is 500^\circ\text{C} . The temperature in kelvin is.  

\begin{aligned}{T_2}&=273+500\\&=773\,{\text{K}}\\\end{aligned}

Substitute the values of temperature and volume in the expression of the Charles' Law.  

\begin{aligned}{V_2}&=\frac{{{T_2}}}{{{T_1}}}{V_1}\\&=\frac{{773\,{\text{K}}}}{{323\,{\text{K}}}}\left({2.33\,{\text{L}}}\right)\\&=5.576\,{\text{L}}\\\end{aligned}

Thus, the volume of the gas at 500^\circ\text{C}} will be \fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}.

Learn More:  

1. Examples of wind and solar energy brainly.com/question/1062501

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Answer Details:  

Grade: High school  

Subject: Physics  

Chapter: Gas law  

Keywords:  

Charles law, temperature, volume, initial, final, kelvin, centigrade, 50 C, 500 degree, 500 C, 50 degree, 2,33 L, gas expand, sample, heated.

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