**Answer:**

The percentage of the weight supported by the front wheel is A= 19.82 %

**Explanation:**

From the question we are told that

The center of gravity of the plane to its nose is

The distance of the front wheel of the plane to its nose is

The distance of the main wheel of the plane to its nose is

At equilibrium the Torque about the nose of the airplane is mathematically represented as

Where m is the mass of the airplane

is the weight of the airplane supported by the main wheel

So

Substituting values

Now the weight supported at the frontal wheel is mathematically evaluated as

Substituting values

Now the weight of the airplane is = mg

Thus percentage of this weight supported by the front wheel is 19.82 %