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Vaselesa [24]
1 year ago
13

Draw the condensed structural formula in the equation for the saponification of trimyristin with koh

Chemistry
2 answers:
Ludmilka [50]1 year ago
4 0

Explanation: Saponification reaction is a reaction in which hydrolysis of fats takes place under basic conditions giving glycerol and a salt of corresponding fatty acid.

We are given a Fatty acid called as Trimyristin.

Its reaction with KOH leads to the formation of soap and is given by the equation:

Trimyristin+3 KOH\rightarrow Glycerol+Soap

C_{45}H_{86}O_6+3KOH\rightarrow C_3H_5(OH)_3+3CH_3(CH_2)_{12}CO_2K

The condensed structural formula for the equation is given in the image attached.

PIT_PIT [208]1 year ago
4 0
<span>Answer: Trimyristin is the triester formed from glycerol and three molecules of myristic acid, a long chain fatty acid. Hydrolysis would be C45H86O6 -> C3H8O3 + 3 C14H28O2</span>
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Explanation:

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= 24 + 28 + 96

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no of moles = given mass / molar mass of the compound

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1.4×148=given mass

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Which of the following compounds would be more soluble in 1 M NH3 than in pure water? BaSO 4 AgBr Pbl 2 BaF 2 Ca(OH) 2
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Answer:

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AgBr(s) + 2NH3(aq) ----> [Ag(NH3)2]^+(aq) + Br^-(aq)

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In a well-constructed response explain the differences and similarities between Natural Selection and Selective Breeding
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6 0
10 months ago
What is the pH at the point of neutralization when 25.00 mL of 0.1000 molar acetic acid (Ka = 1.8 x 10-5) reacts with 25.00 mL o
tatiyna
The equation for the acid base reaction can be written as
     CH3COOH + NaOH → CH3COONa + H2O
We calculate the number of moles of the acid which is equal to the base at equivalence point:
     mol CH3COOH = 0.1000 M * 0.025L = 0.00250 mol
                              = mol H+ reacted = mol OH- used = mol CH3COO-
where the number of moles of salt CH3COONa formed is equal to the number of moles of acid and base.
Using the total volume of the solution, we now compute for the molarity of the salt solution:
     [CH3COO-] = 0.00250 mol/(0.025L + 0.025L) = 0.0500 M
The equation for the hydrolysis reaction by the salt is given by
                       CH3COO- + H2O ⇔ CH3COOH + OH-     
     initial            0.0500                            0              0     
     equilibrium   0.0500-x                         x              x

Using Kw, we write an expression for Kb for the salt:
     Kb (for CH3COO-) = Kw/Ka(for CH3COOH) = 1.0x10-14 / 1.8x10-5
Now solving for the concentration x of OH- formed:
     Kb = x²/(0.0500-x)
approximating that x is negligible compared to 0.0500 simplifies the expression to 
     1.0*10^-14/1.8*10^-5 = x²/0.0500
     x = 5.27*10^-6 = [OH−]
Finally, we calculate pH from pOH:
     pOH = −log(5.27*10^-6) = 5.28
     pH = 14−5.28 = 8.72
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What happens when chlorine atom gains an electron in its outer energy shell?
vfiekz [6]
A neutrally charged chlorine atom becomes a negatively charged chlorine ion.
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