Answer:
a) <u>0.67 moles of O2</u>
b) <u>1.34 moles H2O</u>
c) <u>24.15 grams of H2O</u>
d) <u>21.44 grams O2</u>
Explanation:
Step 1: Data given
Dihydrogen dioxide = H2O2
oxygen gas = O2
Moles H2O2 = 1.34 moles
Molar mass of H2O2 = 34.01 g/mol
Step 2: The balanced equation
2H2O2 → 2H2O + O2
Step 3: Calculate moles of H2O formed
For 2 moles H2O2 we'll have 2 moles H2O produced
For 1.34 moles H2O2 we have <u>1.34 moles H2O</u> produced
This is 1.34 moles * 18.02 g/mol = <u>24.15 grams of H2O</u>
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Step 4: Calculate moles of O2 formed
For 2 moles H2O2 we'll have 1 mol O2 produced
For 1.34 moles H2O2 we'll have 1.34 /2 = <u>0.67 moles of O2 </u>produced
This is 0.67 moles * 32.00 g/mol = <u>21.44 grams O2</u>