**Answer:**

**Explanation:**

**a)**. Find the graph attached for the motion.

**b).** If a shopper walk 5.4 m westwards then 7.8 m eastwards,

Distance traveled by the shopper = Distance traveled in eastwards + Distance traveled westwards

= 5.4 + 7.8

= **13.2 m**

**c).** Displacement of the shopper = Distance walked westwards - Distance traveled eastwards

= 5.4 - 7.8

= -2.4 m

Therefore, **magnitude of the displacement of the shopper is = 2.4 m**

And the **direction of the displacement is eastwards.**

**Answer:**

The distance covered by the projectile is **12.68 m**

**Explanation:**

Given;

angle of projection, θ = 35.0°

speed of projectile, v = 11.5 m/s

The distance covered by the projectile is given by the range of the projection;

R = vt

Therefore, the distance covered by the projectile is **12.68 m.**

**Answer:**

Graph C

**Explanation:**

With the same force and more mass, the position in time will still be parabolic

i.e. x = ½at², but the rate of acceleration will be lower so the position curve will be broader.

**Answer:**

9

**Explanation:**

Speed of space shuttle, v = 7.6 x 10^3 m/s

time of eye blink, t = 110 ms = 0.11 s

length of football field = 91.4 m

Distance traveled by the space shuttle, d

d = speed of shuttle x time

d = v x t

Number of football fields covered = d / length of one football field

=

Thus, the number of football fields covered in the given time is 9.

**Answer:**

**900 km/hr = 9E5 m / 3600 sec = 250 m/sec**

**ah = v^2 / R = 250^2 m/s / 1000 m = 62.5 m/s^2 horizontal acceleration **

**av = 9.8 m/s^2 vertical acceleration (due to gravity)**

**ah / av = 62.5 / 9.8 = 6.38 centripetal acceleration is greater**