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Alekssandra [29.7K]
1 year ago
6

A die with a 10% chance of rolling a 6 is rolled 10 times in a row. What is the probability that a 6 is rolled exactly 2 times?

Mathematics
1 answer:
dolphi86 [110]1 year ago
3 0
P=10C2×<span>.1^2</span>×<span>.9^8.  You should know how to calculate from here.</span>
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The Answer is Pond B, I just took the test!

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On Tuesday 2 2/7 inches of rain fell on Wednesday 1 4/7 inches of rain fell how much more rain fell on tuesday than on Wednesday
Bezzdna [24]

Answer:

5/7

Step-by-step explanation:

Make both of the fractions into improper fractions, 2 2/7 is 16/7 and 1 4/7 is 11/7, then, subtract the improper fractions numerators. 16-11=5.

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HELP ME ASAP PLEASE!!!<br><br>Write the improper fractions for the shaded parts​
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There are 7 6ths in 1 1/6

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galben [10]

1. 45 cents (.10 + .10 + .25= .45)

2. 90 cents (.50 + .40 = .90)

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7 0
1 year ago
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Think about a population mean that you may be interested in and propose a hypothesis test problem for this parameter. Gather app
Sunny_sXe [5.5K]

Answer:

There is no sufficient evidence to conclude that population mean number of times that adults go out for dinner each week is less than 1.5

Step-by-step explanation:

From the question we are told that

   The  population mean is  less than  1.5

   The sample size is  n  =  7

   The sample data is   2, 0, 1, 5, 0, 2, and 3

Generally the sample mean is mathematically represented as  

     \=  x =  \frac{ \sum x_i }{ n }

=>  \=  x =  \frac{ 2 +  0 +  1 +  5 +  0 +  2 +   3 }{ 7 }

=>  \=  x =  1.857

Generally the standard deviation is mathematically represented as

      \sigma  =  \sqrt{\frac{\sum (x_i - \= x)^2}{n} }

=>   \sigma  =  \sqrt{\frac{ (2 -   1.857)^2 +  (0 -   1.857)^2 +\cdots  (3 -   1.857)^2}{7} }

=>   \sigma  =  1.773

The null hypothesis is  H_o :  \mu  =  1.5

The alternative hypothesis is H_a  :  \mu  < 1.5

Generally the test statistics is mathematically represented as

     z  =  \frac{\= x  -  \mu }{ \frac{\sigma }{\sqrt{n} } }

=>   z  =  \frac{\= x  - 1.857 }{ \frac{1.773 }{\sqrt{7} } }  

=>z =  0.53

Generally the p-value is mathematically represented as

      p-value  =  P(z  < 0.53 )

From the z-table  

        P(z  <  0.53 ) =  0.70194

So

       p-value  =  0.70194

From the values obtained we see that p-value  >  0.05  

Here there is no sufficient evidence to conclude that population mean number of times that adults go out for dinner each week is less than 1.5

7 0
1 year ago
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