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gladu [14]
1 year ago
13

For every 3/4 of an hour Saul studies Spanish, he spends 1/5

Mathematics
1 answer:
Hitman42 [59]1 year ago
0 0

Answer & Step-by-step explanation:

The fraction 3/4 can also be written as 0.75. The fraction 1/5 can be written as 0.2. So, we can find the unit rate of the time Saul spends studying French to the time he spends studying Spanish by dividing 0.2 from 0.75.

0.75 ÷ 0.2 = 3.75

So, the unit rate of the time Saul spends studying French to the time he spends studying Spanish is 3 \frac{3}{4} hours.

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Is this right? thank you
Ainat [17]

yes it is right right right 100%

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10 months ago
Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 4t, 1 + 16t, 1 + 52t . Find the points at which their
PtichkaEL [24]

Answer:

Step-by-step explanation:

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4 0
1 year ago
-3(4x + 3) + 4(6x + 1) = x +43 - 13x
MakcuM [25]

Answer:

Hope it helps you☺️☺️

Step-by-step explanation:

-3(4x+3)+4(6x+1)=x+43-13x

or,-12x-9+24x+4=-12x+43

or,12x-5=-12x+43

or,12x+12x=43+5

or,x=48/24

so,x=4

6 0
1 year ago
I have $3,800 in two accounts for one year. The first account earns a yearly interest of 3.5%. The second account earns a yearly
loris [4]

Answer:

-$1000

Step-by-step explanation:

(3800 - x)*3.5/100 = (3800 + x)*6/100

(3800 - x)7/200 = 3/50(3800 + x)

3800 - x = 12/7(3800 + x)

3800 - x = 45600/7 + 12x/7

(19x + 19000)/7 = 0

19x = -19000

x = -$1000.

The minus implies that the investment must occur in the first account, not the second. It wouldn't make sense to add more money into the second account, because the second account already exceeds the $188 interest with the amount it has in there. Therefore $1000 must be added from the second account and invested into the first.

3 0
1 year ago
The radius of a sphere decreases at a rate of 6 m/sec. find the rate at which the surface area decreases when the radius is 20 m
DanielleElmas [232]

The radius of the sphere decreases at the rate of 6 m/ sec

That is, \frac{dr}{dt}=-6

Surface Area of the sphere of radius r is given by S=4\pi r^2

Differentiating with respect to t,

\frac{dS}{dt}=4\pi (2r)\frac{dr}{dt}=8\pi r\frac{dr}{dt}

\frac{dS}{dt}=8\pi (20)^2(-6)=-960\pi \: m^2/sec

8 0
1 year ago
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