**Answer:**

Sorry im a little late but the answer is <u><em>**C)12!**</em></u>

**Step-by-step explanation:**

there are <em>**2 **</em>12's and there is only <em>**1 **</em>of every other number.

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<u><em>**Have a good day, afternoon or day!**</em></u>

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<em>**~Dreamer1331~**</em>

9514 1404 393

**Answer:**

41

**Step-by-step explanation:**

The product of segment lengths from the point of intersection to the circle is the same for both chords.

QC·QE = QD·QF

2x(21) = (x+4)(30)

14x = 10(x +4) . . . . . divide by 3

4x = 40 . . . . . . . . . . subtract 10x

x = 10 . . . . . . . . . . . .divide by 4

2x +21 = EC = 2(10) +21 . . . . . find EC

** EC = 41**

×=8 you're so welcome. :)

**Answer:**

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