Ne (g) effuses at a rate that is times that of Xe (g) under the same conditions.

**Further Explanation:**

**Graham’s law of effusion:
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**Effusion** is the process by which molecules of gas travel through a small hole from high pressure to the low pressure. According to Graham’s law, the effusion rate of a gas is inversely proportional to the s**quare root of the molar mass of gas.
**

The expression for Graham’s law is as follows:

Here,

R is the rate of effusion of gas.

is the molar mass of gas.

Higher the molar mass of the gas, smaller will be the rate of effusion and vice-versa.

The rate of effusion of Ne is expressed as follows:

......(1)

Here,

is the rate of effusion of Ne.

is the molar mass of Ne.

The rate of effusion of Xe is expressed as follows:

......(2)

Here,

is the rate of effusion of Xe.

is the molar mass of Xe.

On dividing equation (1) by equation (2),

......(3)

Rearrange equation (3) to calculate .

......(4)

The molar mass of Ne is 20.17 g/mol.

The molar mass of Xe is 131.29 g/mol.

Substitute these values in equation (4).

Therefore the** rate of effusion of Ne is 2.6 times the rate of effusion of Xe.
**

**Learn more:
**

**1.** Which statement is true for Boyle’s law: brainly.com/question/1158880

**2. **Calculation of volume of gas: brainly.com/question/3636135

**Answer details:
**

**Grade:** Senior School

**Subject:** Chemistry

**Chapter: **Ideal gas equation

**Keywords: **Effusion, rate of effusion, molar mass, Ne, Xe, 2.6 times, Graham’s law, inversely proportional, square root.