I think its c - 2v
v is the speed the object is travelling at
they are saying they it will travel to a point twice the original distance, so 2v
Answer: A car initially traveling at 60 km/h accelerates at a constant rate of 2.0 m/s2. A spaceship far from any star or planet accelerates uniformly from 72 m/s to 160 m/s .
Explanation: i hoped that helped you.
This is a problem based on interference pf light waves.
wavelength of light λ = 553 nm
slit separation d = .134 x 10⁻³ m
screen distance D = 4.5 m
for fourth order bright fringe, path- length difference = 4 x λ
= 4 x 553
= 2212 nm .
= 2.212 μm
Mass of the rider = 50 kg
rate of deceleration of the object = 4.1 m/s/s
now we know by Newton's II law
F = m a
Since the rider is decelerated then let say it will be stopped after moving distance "d"
then we have
Work done to stop the rider
rate of deceleration of the object = 8.2 m/s/s