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e-lub [12.9K]
1 year ago
15

To demonstrate an elastic collision, a teacher places a tennis ball on the floor. She wants to hit the ball so that the followin

g conditions are satisfied.
1. After collision, the tennis ball should roll with the velocity of the ball that hit it
2. At the instant of collision, the ball that hit the tennis ball should stop.
What ball should she use?
Golf ball, tennis ball, basketball, or bowling ball?
Physics
1 answer:
kodGreya [7K]1 year ago
0 0
A tennis ball

The two balls need to have the same mass to meet this condition.
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The acceleration due to gravity on the Moon's surface is known to be about one-sixth the acceleration due to gravity on the Eart
zhannawk [14.2K]

Answer:

Explanation:

If the acceleration due to gravity on the Moon's surface is a_M and the acceleration due to gravity on the Earth is a_E, we can write that:

a_M=\frac{1}{6}a_E

\frac{a_M}{a_E}=\frac{1}{6}

If the radius of the Moon is r_M and the radius of the Earth is r_E, we can write that:

r_M=\frac{1}{4}r_E

\frac{r_M}{r_E}=\frac{1}{4}

By Newton's 2nd Law we know that F=ma and using Newton's law of universal gravitation  we can calculate the gravitational force an object with mass <em>m</em> experiments from a planet with mass <em>M</em> being at a distance <em>r</em> from it. We will assume our object is on the surface so this distance will be the radius of the planet.

Since the force the object experiments is the force of gravitation we can write, for Earth:

F=ma_E=\frac{GM_Em}{r_E^2}

which means:

a_E=\frac{GM_E}{r_E^2}

M_E=\frac{a_Er_E^2}{G}

And for the Moon:

F=ma_M=\frac{GM_Mm}{r_M^2}

which means:

a_M=\frac{GM_M}{r_M^2}

M_M=\frac{a_Mr_M^2}{G}

We can then write the fraction:

\frac{M_M}{M_E}=\frac{a_Mr_M^2}{G}\frac{G}{a_Er_E^2}=\frac{a_M}{a_E}(\frac{r_M}{r_E})^2=\frac{1}{6}(\frac{1}{4})^2=0.01

Which means:

M_M=0.01M_E

3 0
1 year ago
What type of rays are used to locate cavities in teeth?
mote1985 [20]
X-rays are used by dentist to locate cavities in teeth
6 0
1 year ago
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. A circular wire loop 40 cm in diameter has 100 Ohm resistance and lies in a horizontal plane. A uniform magnetic field points
sergeinik [125]

Answer:

(a) 6.283 Wb (b) 69.11 Wb (c) I = 0.628 A

Explanation:

Given that,

The diameter of the loop, d = 40 cm

Radius, r = 20 cm

Initial magnetic field, B = 5 mT

Final magnetic field, B' = 55 mT

Initial magnetic flux,

\phi_i=BA\\\\=5\times 10^{-3}\times \pi \times 20^2\\\\=6.283\ Wb

Final magnetic flux,

\phi_f=B'A\\\\=55\times 10^{-3}\times \pi \times 20^2\\\\=69.11\ Wb

Due to change in magnetic field an emf will be generated in the loop. It is given by :

\epsilon=-\dfrac{d\phi}{dt}\\\\=\phi_f-\phi_i\\\\=69.11-6.283\\\\=62.827\ V

Let I be the current in the loop. We can find it using Ohm's law such that,

\epsilon=IR\\\\I=\dfrac{\epsilon}{R}\\\\I=\dfrac{62.827}{100}\\\\=0.628\ A

Hence, this is the required solution.

7 0
10 months ago
How much work is done by a crane that lowers 1000N of material a distance of 150?
Norma-Jean [14]
The formula is ''w=fd''

So according this fromula we excersise:

W= (1000N) (150)

So we multiply ''1000'' times ''150''

W= 150,000J

Hope i helped! If you need anything else ask me! :)
7 0
1 year ago
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What is the importance of natural resources ?write 5 points ​
Whitepunk [10]
<h2>Hey there! </h2>

<h2>Natural Resource:</h2>

  • The resources, for example, sunshine, air, water, soil, plants, animals, minerals, rivers etc. which after natural formation remain distributed on the earth, are known as natural resource.
  • The natural resources are found in solid, liquid or gaseous states, and in metallic or non metallic form.

<h2>Hope it help you </h2>
5 0
1 year ago
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