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AVprozaik [17]
1 year ago
14

How do you do this question?

Physics
1 answer:
Tema [17]1 year ago
6 0

Answer:

A

Explanation:

Nasty, but doable.

I = 2 amps

R = 8 ohms

V = I * R

V = 2 * 8

V = 16 volts.

========

The 4 ohm resistor sees the same voltage -- 16 volts.

V = 16

R = 4ohms

I = V/R

I = 16/4

I = 4 amps.

The current seen by the unknown resistor R is

It = 4 amps + 2 amps

It = 6 amps

Answer A.

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The volume of liquid flowing per second is called the volume flow rate Q and has the dimensions of [L]3/[T]. The flow rate of li
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Explanation:

We have the following expression for the volume flow rate Q of a hypodermic needle:

Q=\frac{\pi R^{n}(P_{2}-P_{1})}{8\eta L}  (1)

Where the dimensions of each one is:

Volume flow rate Q=\frac{L^{3}}{T}

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Length of the needle L=L

Pressures at opposite ends of the needle P_{2} and P_{1}=\frac{M}{LT^{2}}

Viscosity of the liquid \eta=\frac{M}{LT}

We need to find the value of n whicha has no dimensions, and in order to do this, we have to rewritte (1) with its dimensions:

\frac{L^{3}}{T}=\frac{\pi L^{n}(\frac{M}{LT^{2}})}{8(\frac{M}{LT}) L}  (2)

We need the right side of the equation to be equal to the left side of the equation (in dimensions):

\frac{L^{3}}{T}=\frac{\pi}{8} \frac{ L^{n}}{LT}  (3)

\frac{L^{3}}{T}=\frac{\pi}{8} \frac{ L^{n-1}}{T}  (4)

As we can see n must be 4 if we want the exponent to be 3:

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\frac{L^{3}}{T}=\frac{\pi}{8} \frac{ L^{3}}{T}  (6)

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