sot=8.806sandnowapply1steqo²fmotiontofindoutvfsovf=vi+gt,vf=0+9.8×8.806,vf=86.298andifyouwanttoverifythateitherthisisansweriscorrectornotsoputthevalueoftinsecondeqofmotionandifyougotdistancesameasgiveinthequestionsoyourvalueoftisconsideredascorrectlikewises=vit+1/2gt²,s=0+1/2×9.8(8.806)²,s=4.9×77.55,s=380m(proved)I hope it would be helpfull
The light is a wave that has travels from two different places, each side of the circular obstacle, so an interference process must be given, which is described by the expression
a sin θ = m λ
Where a is the size of the slit, λ the wavelength and m an integer that indicates the order of diffraction.
In the case of the central point, the difference in the optical path of each ray stop is zero, which implies that in some it is also zero, so the waves are in phase for this point and a bright spot must be seen in the center.
When reviewing the answer the correct one is the A