**Answer:**

The location is at (3.535, 1.162) m

**Solution:**

As per the question:

Mass of the projectile, m = 9.6 kg

Initial velocity, v = 12.4 m/s

Angle,

Mass of one fragment, m = 6.5 kg

Time taken by the fragment, t = 1.42 s

Height of the fragment, y = 5.9 m

Horizontal distance, x = 13.6 m

Now,

To determine the location of the second fragment:

Horizontal Range,

Time of flight, t' =

Now, for the fragments:

Mass of the other fragment, m' = M - m = 9.6 - 6.5 = 3.1 kg

Distance traveled horizontally:

Distance traveled vertically:

Now,

x' = 3.535 m

Similarly,

The location of the other fragment is at (3.535, 1.162)