**Answer:**

0.30 mol/L

**Explanation:**

Mass = 108 g

Molar mass of glucose = 180.156 g/mol

The formula for the calculation of moles is shown below:

Thus,

Given Volume = 2 L

<u>**Molarity = 0.3 mol/L**</u>

**Answer:**

Your answer is attached DAME!!!

A.<span>respiration, photosynthesis</span>

**Answer:**

94.58 g of

**Explanation:**

For this question we have to start with the reaction:

Now, we can balance the reaction:

We have the amount of and the amount of
. Therefore we have to find the limiting reactive, for this, we have to follow a few steps.

1) Find the moles of each reactive, using the molar mass of each compound (
).

2) Divide by the coefficient of each compound in the balanced reaction ("2" for and "1" for ).

**<u>Find the moles of each reactive</u>**

**<u>Divide by the coefficient</u>**

**<u />**

The smallest values are for , so hydrogen is the limiting reagent. Now, we can do the calculation for the amount of water:

We have to remember that the molar ratio between and is 2:2 and the molar mass of is 18 g/mol.