Mass = 108 g
Molar mass of glucose = 180.156 g/mol
The formula for the calculation of moles is shown below:
Given Volume = 2 L
<u>Molarity = 0.3 mol/L</u>
Your answer is attached DAME!!!
94.58 g of
For this question we have to start with the reaction:
Now, we can balance the reaction:
We have the amount of and the amount of
. Therefore we have to find the limiting reactive, for this, we have to follow a few steps.
1) Find the moles of each reactive, using the molar mass of each compound (
2) Divide by the coefficient of each compound in the balanced reaction ("2" for and "1" for ).
<u>Find the moles of each reactive</u>
<u>Divide by the coefficient</u>
The smallest values are for , so hydrogen is the limiting reagent. Now, we can do the calculation for the amount of water:
We have to remember that the molar ratio between and is 2:2 and the molar mass of is 18 g/mol.