**Answer:**

- <em>
**About 34% of women will have levels between:**</em>

<em>** **</em><u><em>** 171 mg/dl and 207 mg/dl **</em></u>

**Explanation:**

You might find several intervals of <em>cholesterol levels</em> that contain about 34% of the women.

The easiest way is to find a symmetric interval. This is, with the same number of women below and above the mean.

Then, if <em>34% of the women</em> are within the interval, 100% - 34% = 66% are out of the interval.

For a symmetric interval, half of 66% would be above the median and half-below the median.

Thus, 33% above and 33% below the median.

Now, you can look up the **Z-score** in a **standard normal distribution table.**

There are two types of standard distribution tables: tables that show values that represent the AREA to the LEFT of the Z-score, and tables that show values that represent the AREA to the RIGHT of the Z-score.

Using the second, find the Z-score for a probability of 33%, i.e. 0.33, it is Z-score = 0.44.

That means that the interval must be - 0.44 < Z-score < 0.44

Now that you have the Z-score you can find the cholesterol levels:

For the upper level:

For the lower level:

**Rounding to whole numbers** the interval would be between 171 mg/dl and 207 mg/dl.