**Answer:**

Final pressure 0.105atm

**Explanation:**

Let V1 represent the initial volume of dry air at NTP.

under adiabatic condition: no heat is lost or gained by the system. This does not implies that the constant temperature throughout the system , but rather that no heat gained or loss by the system.

Adiabatic expansion:

273/T2=(5V1/V1)^(1.4−1)

273/T2=5^0.4

Final temperature T2=143.41 K

Also

P1/P2=(V2/V1)^γ

1/P2=(5V1/V1)^1.4

Final pressure P2=0.105atm

**Answer:**

- solution,
- Given
- load =400N
- ld=0.2m
- ed=0.6m
- effort =150N

**Explanation:**

efficiency =output work/input work ×100%

l×ld/e×ed×100%

400×0.2/150×0.6×100%

80/90×100%

88.89%ans

**Answer:**

case x py L is in the positive z direction

case y px L the negative z direction
** **

**Explanation:**

The angular amount is defined by the relation

** L = r x p
**

the bold are vectors, where r is the position vector and p is the linear amount vector.

The module of this vector can be concentrated by the relation

L = r p sin θ

the direction of the vector L can be found by the right-hand rule where the thumb points in the direction of the displacement vector, the fingers extended in the direction of the moment p which is the same direction of speed and the palm points in the direction of the angular momentum L

in the **case x py
**

the thumb is in the x direction, the fingers are extended in the direction and the **palm is in the positive z direction
**

**
**

In the **case y px**

the thumb is in the y direction, the fingers are in the x direction, the palm is i**n the negative z direction**

Answer:

63 cm

Explanation:

Mathematically;

The focal length of a double convex lens is given as;

1/f = (n-1)[1/R1 + 1/R2]

where n is the refractive index of the medium given as 1.52

R1 and R2 represents radius of curvature which are given as 60cm and 72cm respectively.

Plugging these values into the equation, we have:

1/f = (1.52-1)[1/60 + 1/72)

1/f = 0.0158

f = 1/0.0158

f = 63.29cm which is approximately 63cm