**Answer:**

it's c

**Step-by-step explanation:**

**The real solutions to the function is **x = ±5 .

<u>**Step-by-step explanation:**</u>

**Here we have following info:** Look at the work for the following function. What mistake did they make when using the quadratic formula to find the solutions? What are the real solutions to the function?

**
Let's check step by step:**

**Step 1: 9±−92−4(1)(20)√2(1) **

Formula is :

⇒

⇒

**Step 2: 9±−81−80√2
**

**Step 3: 9±−161√2
**

**Mistake here is instead of subtracting , 81 & 80 are added!**

More precisely , x = ±5

**Step 4: There are no real solutions.**

**Wrong statement!**

**∴The real solutions to the function is **x = ±5 .

I think it's the first option

**Answer:**

sides are proportional and angles are congruent

**Step-by-step explanation:**

Every segment in ABCDEFG is parallel to, and double the length of, the corresponding segment in HIJKLMN. All corresponding angles are congruent. Thus, the definition of similar polygons is met:

- corresponding sides are proportional
- corresponding angles are congruent.

You could find the surface area using two different methods, but coming out with the same answer.

**Method One:** This method involves using an equation that helps finding the surface area for a square pyramid.

The equation: A+(1/2)ps=SA; we should break down what the letters stand for. A=Area of the base; the area of the base is 10×10=100 P= perimeter of the base; 10×4=40 S= Slant height;14

Let's put these values into the equation and find the surface area. 100+(1/2)(40)(14)=100+(20)(14)=100+280=380 The surface area is 380 in².

**Method Two: ** The picture below shows how to lay out the square pyramid so you can find the area of each the shapes, then add them up. There are four triangles and a square.

Triangles: We use the equation (1/2)BH; let's plug the values in. 1/2(10)(14)=1/2(140)=70; there are four triangles, so let's multiply by four to find the area of all four of them triangles together. 70×4=280

Square: It's the side length squared. 10²=100; let's add everything together.

The four triangles+the square= the surface area

280+100=380

**So, the surface area is 380 in².**