Here we have following info: Look at the work for the following function. What mistake did they make when using the quadratic formula to find the solutions? What are the real solutions to the function?
Let's check step by step:
Step 1: 9±−92−4(1)(20)√2(1)
Formula is :
Step 2: 9±−81−80√2
Step 3: 9±−161√2
Mistake here is instead of subtracting , 81 & 80 are added!
You could find the surface area using two different methods, but coming out with the same answer.
Method One: This method involves using an equation that helps finding the surface area for a square pyramid.
The equation: A+(1/2)ps=SA; we should break down what the letters stand for. A=Area of the base; the area of the base is 10×10=100 P= perimeter of the base; 10×4=40 S= Slant height;14
Let's put these values into the equation and find the surface area. 100+(1/2)(40)(14)=100+(20)(14)=100+280=380 The surface area is 380 in².
Method Two: The picture below shows how to lay out the square pyramid so you can find the area of each the shapes, then add them up. There are four triangles and a square.
Triangles: We use the equation (1/2)BH; let's plug the values in. 1/2(10)(14)=1/2(140)=70; there are four triangles, so let's multiply by four to find the area of all four of them triangles together. 70×4=280
Square: It's the side length squared. 10²=100; let's add everything together.