<span>**the complete question in the attached figure**</span>

A) The points in the table are

(0,84) (1,146) (2,208) (3,270)

<span><span> To find the equation of the line------- > y=mx+b-------- > </span>select two points</span>(0,84) (1,146)

<span> m=(y2-y1)/(x2-x1)------->
m=(146-84)/(1-0)=62/1=62</span>

84=62*0+b-------------- > b=84

Then

y=62x+84

**the answer to the question A is y=62x+84**

B) Equation of remaining gasoline is g=16-(1/20)*d

<span>a) </span>For d=100 miles

g=16-(1/20)*100=11 gallons

<span>b) </span>For d=200 miles

g=16-(1/20)*200=6 gallons

<span>c) </span>For d=300 miles

g=16-(1/20)*300=1 gallons

C) Using a graphic
tool ----------- > view the graphic in file attached

g=16-(1/20)*d

D) Explain why the slope of the drawn line in part C must be negative

The slope is negative because as the car advances gasoline is
consumed to the point (320.0)

<span>When the gasoline is zero (g=0) </span>the car has traveled 320 miles