From the question, The distance from where the projectile was lunched to where its land is the range(R) of the projectile
R = (U²sin2Ф)/g.................... Equation 1
Where U = initial velocity of the projectile, Ф = angle above the horizontal, g = acceleration due to gravity.
Given: U = 45 m/s, Ф = 30°
Constant: g = 9.8 m/s²
Substitute these values into equation 1
R = (45²sin30°)/9.8
R = 2025(0.5)/9.8
R = 103.32 m.
use a = (v1-v2)/t so u would put 14 (initial velocity or v 1) - 6 (the v2) and divide all of that by 4 seconds to get 2m/s/s as your acceleration
A. (200i + 85j - 30k)m
C. 219.37 m
UP: +VE Z
NORTH: +VE Y
EAST: +VE X
DISPLACEMENT : (0.2*1000 i + (-15+0.1*1000)j + (-3*10)k) m
= (200i + 85j - 30k)m
B. total distance = 10*3+15+200+100 = 345m
Magnitude = = 219.37 m
unit vector =
True. They are also made of helium and hydrogen!