It sets a condition: When thex and y units add to 90, tanx= recoprocal of tany

The chart gives the values of trig. function when at certain degrees. When we looks ar tanΘ, we are given the x and y values, becuase tanΘ= y/x

Answer:

Perimeter = 25

Step-by-step explanation:

J(-2, 5)

K(1, 1)

L(1, -1)

M(-5, -4)

N(-5, 1)

Formula for distance between 2 coordinates is;

d = √((x_2 - x_1)² + (y_2 - y_1)²)

Thus;

JK = √((1 - (-2))² + (1 - 5)²)

JK = √25

JK = 5

KL = √((1 - 1)² + (-4 - 1)²)

KL = √25

KL = 5

LM = √((-5 - (-1))² + (-4 - (-1))²)

LM = 5

MN = √((-5 - (-5))² + (1 - (-4))²)

MN = 5

JN = √((-5 - (-2))² + (1 - 5))²)

JN = 5

Thus;

Perimeter = 5 + 5 + 5 + 5 + 5

Perimeter = 25

**Answer: $43**

**Step-by-step explanation: 860 x 0.05 = 43**

4.7 = x - 3.7

add 3.7 to both sides

4.7 + 3.7 = x

x = 7.4

**Answer:**

**The area of the given figure is .**

**Step-by-step explanation:**

To find out the area we should have to redraw the figure having nomenclature ABCDE and join BD. Thus we have a rectangle ABDE and a triangle BCD.

The new figure is in the attachment.

Given,

Length of AE = 7 cm

Length of DE = 8 cm

Length of CF = 11 cm

Solution,

Area of rectangle ABDE =

**Area of ABDE = **

Now for triangle BCD,

Length of BD = length of AE = 7 cm

Length of GF = Length of DE = 8 cm

∴ Length of CG = Length of CF-Length of GF =

Area of triangle BCD =

**Area of BCD = **

**Area of ABCDE =** **Area of ABDE + Area of BCD = **

**Thus the area of the given figure is .**