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Andre45 [30]
1 year ago
6

Which of the following is a useful policy to minimize waste and mistakes?

Computers and Technology
1 answer:
anastassius [24]1 year ago
5 0

Answer:

Option C

Explanation:

To ensure correct input data, proper  procedure is must in order to minimize waste and mistakes.

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Although computers play an important supporting role as a tool in the discipline, they are just that–tools. ... Given a problem, a computer scientist's goal is to develop an algorithm, a step-by-step list of instructions for solving any instance of the problem that might arise.

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The ____ package contains frequently used classes and is implicitly imported into java programs.
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When visiting a museum Liam takes a photo of a painting with a smartphone which stores to image file. Which of the folllowing be
Maslowich

Answer: D. The phone can represent the photo in either digital or analog formats depending on the sampling technique that is used

Explanation:

Photos can either come out as analog or digital with digital formats having better overall quality overall. Digital photos are taken with digital cameras and so use electronic detectors while analog photography uses chemical processes.

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5 0
1 year ago
, , and angle x and angle y are both in the first quadrant.
maks197457 [2]

Answer:

\tan(x+y) = 3.73

Explanation:

The missing part of the question are:

\sin(x) = \frac{1}{2}

\cos(y) = \frac{\sqrt 2}{2}

Required

\tan(x + y)

First, we calculate \sin(y) and \cos(x)

We have:

\sin^2(x) + \cos^2(x) = 1

So:

(1/2)^2 + \cos^2(x) = 1

Collect like terms

\cos^2(x) = 1 - (1/2)^2

\cos^2(x) = 1 - \frac{1}{4}

Take LCM

\cos^2(x) = \frac{4-1}{4}

\cos^2(x) = \frac{3}{4}

Square roots of both sides

\cos(x) = \frac{\sqrt 3}{2}

Similarly,

\sin^2(y) + \cos^2(y) = 1

So:

\sin^2(y)+(\sqrt 2/2)^2 = 1

\sin^2(y)+ (2/4) = 1

\sin^2(y)+1/2 = 1

Collect like terms

\sin^2(y) = 1 - 1/2

Take LCM

\sin^2(y) = \frac{2 -1}{2}

\sin^2(y) = \frac{1}{2}

Square roots of both sides

\sin(y) = \frac{1}{\sqrt2}

Rationalize

\sin(y) = \frac{\sqrt2}{2}

So, we have:

\sin(x) = \frac{1}{2}           \cos(x) = \frac{\sqrt 3}{2}

\cos(y) = \frac{\sqrt 2}{2}        \sin(y) = \frac{\sqrt2}{2}

\tan(x) = \sin(x) \div \cos(x)

\tan(x) = \frac{1}{2} \div \frac{\sqrt 3}{2}

Rewrite as:

\tan(x) = \frac{1}{2} * \frac{2}{\sqrt 3}

\tan(x) = \frac{1}{\sqrt 3}

Rationalize

\tan(x) = \frac{\sqrt 3}{3}

Similarly

\tan(y) = \sin(y) \div \cos(y)

\tan(y) = \frac{\sqrt 2}{2} \div \frac{\sqrt 2}{2}

\tan(y) = 1

Lastly,

\tan(x + y)= \frac{\tan(x) + \tan(y)}{1 - \tan(x) \cdot \tan(y)}

\tan(x + y)= \frac{\frac{\sqrt3}{3} + 1}{1 - \frac{\sqrt3}{3} \cdot 1}

\tan(x + y)= \frac{\frac{\sqrt3}{3} + 1}{1 - \frac{\sqrt3}{3}}

Combine fractions

\tan(x + y)= \frac{\frac{\sqrt3+3}{3}}{\frac{3 - \sqrt3}{3}}

Cancel out 3

\tan(x + y)= \frac{\sqrt3+3}{3 - \sqrt3}

Using a calculator

\tan(x+y) = 3.73

5 0
1 year ago
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