This is a kinematic problem that asks us to determine the velocity of an object in a time frame given the plot of time in the x-axis and distance,x, in the y-axis. The figure that shows the behavior of the object is shown in the diagram. Segment C is going down which means the object is decelerating indicated by the negative slope. E on the other hand also has a negative slope as the line is also going down but less steep than that of c. slope is equal to change in y over the change in x. So given a definite change in y, a shorter change in x would make a greater slope, hence, becoming steeper. The speed then is C is higher than the speed in E.
It could be rock music because of his face expresion
Answer:
B
Explanation:
Forces are pushes or pulls. They can be balanced or unbalanced. If unbalanced they can change the shape of objects and change the way they are moving (speed-wise)
Answer:
ΔX = 0.0483 m
Explanation:
Let's analyze the problem, the car oscillates in the direction y and advances with constant speed in the direction x
The car can be described with a spring mass system that is represented by the expression
y = A cos (wt + φ)
The speed can be found by derivatives
= dy / dt
= - A w sin (wt + φ
So that the amplitude is maximum without (wt + fi) = + -1
= A w
X axis
Let's reduce to the SI system
vₓ = 15 km / h (1000 m / 1 km) (1h / 3600s) = 4.17 m / s
As the car speed is constant
vₓ = d / t
t = d / v
ₓ
t = 4 / 4.17
t = 0.96 s
This is the time between running two maximums, which is equivalent to a full period
w = 2π f = 2π / T
w = 2π / 0.96
w = 6.545 rad / s
We have the angular velocity we can find the spring constant
w² = k / m
m = 1200 + 4 80
m = 1520 m
k = w² m
k = 6.545² 1520
k = 65112 N / m
Let's use Newton's second law
F - W = 0
F = W
k x = W
x = mg / k
Case 1 when loaded with people
x₁ = 1520 9.8 / 65112
x₁ = 0.22878 m
Case 2 when empty
x₂ = 1200 9.8 / 65112
x₂ = 0.18061 m
The height variation is
ΔX = x₁ -x₂
ΔX = 0.22878 - 0.18061
ΔX = 0.0483 m
Explanation:
Newtons 1st law :
A body or object is in a state of continuous motion or in a state of rest unless an outside force is applied to it.
Newtons 2nd law :
Newtons second law states that the force applied is directly proportional to the mass of the body and the acceleration with which it travels.
Newtons 3rd law :
Every force applied has an equal and opposite force.
a). Newtons 3rd law
b). Newtons 2nd law
c). Newtons 1st law
d). Newtons 3rd law
e). Newtons 1st law
