The work done is 8075.2 J.
Mass of crate = 160 kg
Distance = 10.3 m
coefficient of friction = 0.50
We need to calculate the normal force
Using balance equation
Here, acceleration a = 0
Put the value into the formula
We need to calculate the frictional force
We need to calculate the work done
Using formula of work done
Hence, The work done is 8075.2 J.
Acceleration = 10m/s²
Time of fall = 9s
Final velocity = ?
We can assume that the cart falls from rest.
Initial velocity = 0m/s
v = u + gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 0 + 10 x 9 = 90m/s
According to the <span> Newton's second law of motion</span>:
Force = mass × acceleration
Acceleration = change in speed ÷ time
Force =mass × (change in speed/time)
Acceleration = 40 m/s ÷ 1.1 millisecond
Acceleration = 40 m/s ÷ 0.001 seconds
Acceleration = 40,000 m/s²
F = m × a
F = 0.155 kg × 40,000 m/s²
F = 4,600 kg·m/s² (Newtons)
We can use the result of applying the Gauss theorem to a infinite line of charge
with r the perpendicular distance to the line of charge. The total field will be the sum of the contribution to the field by each line of charge.
In this case the field is directed toward the line of charge placed in y=1m