Nitrogen, Oxygen, and Fluorine do not follow this trend. The noble gas electron configuration will be close to zero because they will not easily gain electrons.
Answer:
Explanation:
honesty i just know it has to be b or d because bases don’t donate. acids donate.
N2 + 3H2 ---> 2NH3
nitrogen + hydrogen ---> ammonia
Answer:
6.40x10^-7
Explanation:
answer with work is attached.
Answer:
Lead chromate form = 0.97 g
Explanation:
The Balanced chemical equation of the given reaction is as follows
K₂CrO₄ + Pb(NO₃)₂ → PbCrO₄ + 2 KNO₃
<u>Given that</u>
Mass of Pb(NO₃)₂ = 1 g

Mole of 25 ml of 1.00 (M) K₂CrO₄
Mole = 25 x 1 milimol = 25 x 10⁻³
Using mole ratio method to find<u> limiting reagent </u>
Hence K₂CrO₄(potassium chromate) is a<u> limiting reagent.</u>
So lead chromate formed = mole X molar mass
= 0.003 X 323.19 g
= 0.97 g
∴ 0.97 g lead chromate form when a 1.00-g sample of Pb(NO₃)₂ is added to 25.0 ml of 1.00 M K₂CrO₄ solution.