A 1.34 mole sample of LiCl dissolves in water, The volume of the final

<u>Answer: </u>The molecular weight of the dibasic acid is 89.6 g/mol

<u>Explanation:</u>

Normality is defined as the amount of solute expressed in the number of gram equivalents present per liter of solution. The units of normality are eq/L. The formula used to calculate normality:

     ....(1)

We are given:

Normality of solution =

Given mass of solute = 0.56 g

Volume of solution = 250 mL

Putting values in equation 1, we get:

Equivalent weight of an acid is calculated by using the equation:

  .....(2)

Equivalent weight of acid = 44.8 g/eq

Basicity of an acid = 2 eq/mol

Putting values in equation 2, we get:

Hence, the molecular weight of the dibasic acid is 89.6 g/mol

Answer:

.0000084

Explanation:

Your answer is 3! Hope you get a good grade :)♥

Think of it this way: say orbitals are boxes and each box can contain 2 electrons.

If there are 3 boxes forming one orbital, it takes 6 electrons to completely fill it. Since there's less than six, each box takes one electron, so there's 1 electron per orbital.

This is true. It has two electrons in shell one, 8 in shell two, and one in shell three.

Hope this helped