Answer:
The acceleration is 6 
Explanation:
Use Newton's second law to solve the problem:

(a) The speed of the mass m2 just before it hits the floor for frictionless table is 1.98 m/s.
(b) The speed of the mass m2 just before it hits the floor when there is friction is 1.53 m/s.
<h3>Apply Newton's second law of motion for object m₁</h3>

<h3>Apply Newton's second law of motion for object m₂</h3>

Solve (1) and (2) together

When the table is frictionless, the acceleration of the masses is calculated as follows;

When the coefficient of friction between m1 and the table is 0.2, the acceleration of the masses is calculated as follows;

The height of the mass m2 above the ground = 60 cm = 0.6
<h3>Speed of the mass for frictionless table</h3>
The speed of the mass m2 just before it hits the floor for frictionless table is calculated as follows;

<h3>The speed of the mass when there is friction</h3>
The speed of the mass m2 just before it hits the floor when there is friction is calculated as follows;

Learn more about acceleration mass over a pulley here: brainly.com/question/13376070
Answer:
duplication being slightly more expensive.
Explanation:
The ration of the rms speed of 235uf6 to that of 238uf6 is 1.004.
The molecular mass of 235uf6 is 349, while that of 238uf6 is 352.
The rms speed is calculated as
v=√(3RT/m)
Thus the ratio rms speed of 235uf6 to 238uf6 is calculated as
r=√(352/349)=1.004
Answer:
A and D
Explanation:
Acceleration is the active change in speed, increasing or decreasing.