**Answer:**

The acceleration is 6

**Explanation:**

Use Newton's second law to solve the problem:

(a) The **speed **of the **mass m2** just before it hits the floor for **frictionless** table is **1.98 m/s.**

(b) The **speed **of the **mass m2** just before it hits the floor when **there is friction** is **1.53 m/s.**

<h3>Apply Newton's second law of motion for object m₁</h3>

<h3>Apply Newton's second law of motion for object m₂</h3>

Solve (1) and (2) together

When the table is **frictionless**, the **acceleration **of the **masses **is calculated as follows;

When the** coefficient of friction** between **m1 **and the **table **is 0.2, the **acceleration **of the **masses **is calculated as follows;

The **height **of the **mass m2** above the ground = 60 cm = 0.6

<h3>Speed of the mass for frictionless table</h3>

The **speed **of the **mass m2** just before it hits the floor for **frictionless** table is calculated as follows;

<h3>The speed of the mass when there is friction</h3>

The **speed **of the **mass m2** just before it hits the floor when **there is friction** is calculated as follows;

Learn more about** acceleration mass over a pulley** here: brainly.com/question/13376070

**Answer:**

duplication being slightly more expensive.

**Explanation:**

The ration of the rms speed of 235uf6 to that of 238uf6 is **1.004.**

The molecular mass of 235uf6 is 349, while that of 238uf6 is 352.

The rms speed is calculated as

v=√(3RT/m)

Thus the ratio rms speed of 235uf6 to 238uf6 is calculated as

r=√(352/349)=1.004

**Answer:**

**A and D**

**Explanation:**

Acceleration is the active change in speed, increasing or decreasing.