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Furkat [3]
1 year ago
6

Jocko the clown, whose mass is 60-Kg, stands on a skateboard. A 20-Kg ball is thrown at Jocko at 3m/s, and when he catches the b

all, he and the ball move on the skateboard. How fast do Jocko and the ball move after he catches the ball?
Physics
1 answer:
Mekhanik [1.2K]1 year ago
7 0

Answer:

The speed of the Jocko and the ball move after he catches the ball is 0.75 m/s.

Explanation:

Given that,

Mass if Jocko, m = 60 kg

Mass of the ball, m' = 20 kg

Speed of the ball, v = 3 m/s

Let V is the speed of Jocko and the ball move after he catches the ball. The momentum of the system remains conserved. Using the conservation of momentum as :

m'v'=(m+m')V\\\\V=\dfrac{m'v'}{(m+m')}\\\\V=\dfrac{20\times 3}{(60+20)}\\\\V=0.75\ m/s

So, the speed of the Jocko and the ball move after he catches the ball is 0.75 m/s.

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A child on a sled is perched at the top of a hill, at a height 7.0 m above the base of the hill. The total mass of the girl plus
spin [16.1K]

Answer:

a)11,71 m/s

b)12.73 m/s

Explanation:

We apply the conservation principle because there is no friction between the hill and the sled:

Total initial energy (Ei) = Total initial energy (Ef), Equation(1)

We define:

K = Kinetic energy = \frac{1}{2}*m*v^{2}

U = Potential energy = m*g*h

m = mass (kg)

v = velocity (m/s)

h = height (m)

g = gravity acceleration = 9.8m/s^{2}

A)  hi=7m, hf=0 ,vi=0 , vf=?

   Ei=Ef\\Ki+Ui=Kf+Uf

1/2*m*vi^{2} +m*g*hi= 1/2*m*vf^{2} +m*g*hf

0+m*g*hi=1/2*m*vf^{2}+0

(2*m*g*hi)/m=vf^{2}

vf=\sqrt{2*g*hi}

vf=\sqrt{2*9.8*7}

vf=11.71 m/s

Answer: She reaches the base of the hill with speed of 11.22 m/s

B) hi=7 m, vi=5 m/s, hf=0, vf=?

m*g*hi+1/2*m*vi^{2} =m*g*hf+1/2*m*vf^{2}

We divide all terms by m

g*hi+1/2vi^{2} =g*hf+1/2*vf^{2}

9.8*7+1/2*5^{2} =1/2*vf^{2}

2(68.6+12.5)=vf^{2}

162.2=vf^{2}

vf=\sqrt{162.2}

vf=12.73 m/s

Answer: She will move with a speed of 12.73 m/s when she reaches the base of the hill

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A body oscillates with simple harmonic motion along the x axis. Its displacement varies with time according to the equation x =
frutty [35]

Answer:

θ = (7π / 3) rad

Explanation:

given,

displacement of simple harmonic motion along x-axis

equation is given as

                   x = 5 sin (π t + π/3 )

general equation of simple harmonic motion

                   x = A sin θ

           θ is the phase angle

      θ = π t + π/3

at   t = 2 s

      \theta =\pi \times 2 +\dfrac{\pi}{3}

      \theta =\dfrac{7\pi}{3}\ rad

Phase of the motion at t =2 s is θ = (7π / 3) rad

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The SI unit of force is the A. meter. B. joule. C. newton. D. kilogram.
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The SI unit of force is the newton.
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