The speed of the Jocko and the ball move after he catches the ball is 0.75 m/s.
Mass if Jocko, m = 60 kg
Mass of the ball, m' = 20 kg
Speed of the ball, v = 3 m/s
Let V is the speed of Jocko and the ball move after he catches the ball. The momentum of the system remains conserved. Using the conservation of momentum as :
So, the speed of the Jocko and the ball move after he catches the ball is 0.75 m/s.
We apply the conservation principle because there is no friction between the hill and the sled:
Total initial energy (Ei) = Total initial energy (Ef), Equation(1)
K = Kinetic energy =
U = Potential energy =
m = mass (kg)
v = velocity (m/s)
h = height (m)
g = gravity acceleration =
A) hi=7m, hf=0 ,vi=0 , vf=?
Answer: She reaches the base of the hill with speed of 11.22 m/s
B) hi=7 m, vi=5 m/s, hf=0, vf=?
We divide all terms by m
Answer: She will move with a speed of 12.73 m/s when she reaches the base of the hill
θ = (7π / 3) rad
displacement of simple harmonic motion along x-axis
equation is given as
x = 5 sin (π t + π/3 )
general equation of simple harmonic motion
x = A sin θ
θ is the phase angle
θ = π t + π/3
at t = 2 s
Phase of the motion at t =2 s is θ = (7π / 3) rad
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