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makkiz [27]
1 year ago
12

Earth’s atmosphere is in hydrostatic equilibrium. What this means is that the pressure at any point in the atmosphere must be hi

gh enough to support the weight of air above it. How would you expect the pressure on Mt. Everest to differ from the pressure in your classroom? Explain why.
Physics
1 answer:
Misha Larkins [42]1 year ago
6 0

Answer: The pressure that one experiences on the Mount Everest will be different from the one, in a classroom. It is because pressure and height are inversely proportional to each other. This means that as we move up, the height keeps on increasing but the pressure will keep on decreasing. This is the case that will be observed when one stands on the Mount Everest as the pressure is comparatively much lower there.

It is because as we move up, the amount of air molecules keeps on decreasing but all of the air molecules are concentrated on the lower part of the atmosphere or on the earth's surface.

Thus a person in a low altitude inside a classroom will experience high pressure and a person standing on the Mount Everest will experience low pressure.

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A mass weighing 30 lbstretches a spring . The mass is also attached to a damper with coefficient . Determine the value of for wh
LUCKY_DIMON [66]

Answer:

the damping coefficient when the system is critically damped is 13.42 lb s/ft.

Explanation:

The directions are missing the last part, which is:

"A mass weighing 30 lb stretches a spring 7.5 in. The mass is also attached to a damper with coefficient γ. Determine the value of γ for which the system is critically damped. Assume that g = 32 \cfrac {ft}{s^2}

Round your answer to three decimal places."

The spring system is determined by the following differential equation

my''+\gamma y'+ky=0

where \gamma is the damping coefficient, thus it is critically damped when the system transitions from real to complex solutions that happens at

\gamma_^2 -4km=0

Solving for the damping coefficient.

\gamma^2 = 4km\\ \gamma = \sqrt{4km}

where the spring constant k is given by

k = \cfrac{mg}{L}\\k = \cfrac wL\\

And the mass is given by

mg = w\\ m = \cfrac wg

So the damping coefficient will be

\gamma = \sqrt{4\cfrac wL \cfrac wg}\\\gamma = \sqrt{4\cfrac {w^2}{gL}}

Replacing the given information we have:

\gamma = \sqrt{4\cfrac {(30\, lbs)^2}{32\cfrac{ft}{s^2}0.625 ft}

Thus we get

\gamma = 13.42 \cfrac{lb \cdot s}{ft}

The value of the damping coefficient when the system is critically damped is 13.42 lb s/ft.

4 0
1 year ago
Which BMI standard for teens is considered under weight?
Lena [83]
First let’s pick one at random

Less than 5 percentile

That means they lined 100 kids up and less than 5% of them are that certain weight.

So if you apply this to every option you will see the answer is
A). Less than 5 percentile
3 0
1 year ago
Read 2 more answers
How to calculate percentage of its kinetic energy
olga_2 [115]

Answer:

Use the formula =1/2^2

KE = kinetic energy

m = mass of a body

v = velocity of a body

kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s^2.

* Hopefully this helps:) Mark me the brainliest:)!!!

7 0
1 year ago
At which point will the riders experience centripetal acceleration?
Umnica [9.8K]

As we know that centripetal acceleration is given as

a = \frac{v^2}{R}

so here we all know that radius of curvature of straight surface or flat surface is infinite or very large

So here acceleration will be zero when it move on flat surface

So here at points "w" , "x" , "z" the surface will be flat surface

and hence the observer will not experience centripetal acceleration

while at point Y the surface is curved and hence the observer will experience centripetal acceleration

3 0
1 year ago
To determine power, it is necessary to know the
Lady_Fox [76]

Force, distance and time

Explanation:

Power is the rate at which work is being done:

 Power = \frac{Force x distance }{time taken}

The quantity force x distance is the work done by a body.

Force is the applied pull or push on a body that causes it change position.

It is important to know the work done and the time taken for the work to be done when considering power.

The unit of power is watt or J/s

learn more:

Power brainly.com/question/10421964

#learnwithBrainly

7 0
1 year ago
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