a cone shaped funnel can hold 314 cubic inches of water. if the height of the funnel is 12 inches what is the radius of the funn

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1 year ago

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2 answers:

Sloan [31] · Answer 1 · 2020-11-28T02:57:18+03:00

The radius of cone shaped funnel is 5 inches

<u>Solution:</u>

To calculate the volume of a cone, we have to multiply the base area, in this case the area of a circle:

$\pi r^2$ by its height and by $\frac{1}{3}$

$\bold{Volume \ of \ a \ cone \ is \ \frac{1}{3} \times \pi\times r^2\times h}$

Here, volume = 314; h = 12;

we already know $\bold{\pi=3.14}$

On substituting the vales we get,

$314=\frac{1}{3}\times 3.14\times r^2\times 12$

Bringing 3.14 to the L.H.S,

$\frac{314}{3.14}=\frac{1}{3}\times r^2\times12$

On solving we get,

$100=4\times r^2$

$\frac{100}{4}=r^2$

On dividing 100 and 4 we get,

$25=r^2$

Taking roots on both sides,

$\sqrt25=\sqrt{r^2}$

$\sqrt{5\times5}=\r$

$\therefore r=5$

Hence, radius = 5 inches

lisov135 [29] · Answer 2 · 2020-11-28T01:23:21+03:00

4 0

Answer: Radius = 5inches

Step-by-step explanation:

Volume of a cone = 1/3πr²h

314 = 1/3 X 3.142 X r² X 12

314 = 37.704/3 X r²

314 = 12.568 X r²

r² = 314/ 12.568

r² = 24.9

r = √24.9

r = 4.98 ~ 5 inches