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sergeinik [125]
1 year ago
8

A wire is bent into three circular segments, each of radius r-10 cm, each segment is quadrant of a circle, ab

Physics
1 answer:
Leya [2.2K]1 year ago
7 0

Answer:

Jajakakajahajakakiaja

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Driving a motor vehicle often requires __________ reaction time.
Anastasy [175]

It often requires STANDARD reaction time

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1 year ago
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An empty coal car of a train of mass 8000 kg is moving at 12 m/s along rails. 24000 kg of coal is dumped into the car from a mot
ZanzabumX [31]

Answer:

3 m/s

Explanation:

Initial = Final

Mass * Velocity = Mass *Velocity

8000kg * 12m/s = (8000kg+ 24000kg) * (Final Velocity)

(96000 kgm/s) / (32000kg) = (Final Velocity)

Final Velocity = 3 m/s

7 0
3 months ago
The average cheetah in this town cheetah race runs 16 miles per hour. But, another cheetah won the race because it ran 20 miles
Harrizon [31]

Answer: 110 miles per hour

Explanation:

We know that every hour, the cheetah runs 20 miles.

So, we have to multiply this number by 5, then 1/2.

20 x 5 = 100.

We know that 1/2 of 20 is 10 because 20 ÷ 2 = 10.

So, we add on 10 to 100.

We get 110 as an final result. Hope this helps!

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1 year ago
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Un día de tormenta vemos un rayo y cronometramos el tiempo que tarda en escucharse el trueno. El resultado es de 12 s. ¿A qué di
KatRina [158]

Answer:

4

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1 year ago
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A CIRCULAR COIL OF 20 TURNS OF RADIUS 10.0 cm IS PERPENDICULAR TO A 0.30 tesla MAGNETIC FIELD. HOW MUCH INDUCED emf IS CREATED W
attashe74 [19]

Answer:

1.57 V

Explanation:

The induced emf ε = -ΔΦ/Δt where Φ = magnetic flux = NABcosθ where N = number of turns of circular coil = 20, A = area of coil = πr² where r = radius of coil = 10.0 cm = 0.1 m , B = strength  of magnetic field = 0.30 T,θ = angle between normal to are and magnetic field and Δt = change in time = 0.12 s

Now ΔΦ = change in magnetic flux through circular coil = Φ' - Φ

Φ = magnetic field when A is perpendicular to B , that is θ = 90°. So, Φ = NABcos90 = 0 and Φ' = magnetic field when A is parallel to B , that is θ = 0°. So, Φ' = NABcos0 = NAB

So, ΔФ = Ф' - Ф

= 0 - NAB

= -NAB

= -Nπr²B

= -20 × π(0.1 m)² × 0.30 T

= -0.19 Wb

So, ε = -ΔΦ/Δt

= -(-0.19 Wb)/0.12 s

= 1.57 Wb/s

= 1.57 V

6 0
1 year ago
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