The charge on the plates of a parallel plate capacitor determines which of the following? Select all that apply. The electric fi

Question

1 year ago

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eld across the plates. The potential across the plates. The capacitance of the capacitor. The current in the circuit. The resistance of the circuit.

1 answer:

Leviafan [203] · Answer 1 · 2020-09-20T23:55:38+03:00

Electric field between the plates of capacitor is given by

$E = \frac{Q}{A\epsilon_0}$

potential difference between the plates of capacitor is given by

$V = E.d$

$V = \frac{Qd}{A\epsilon_0}$

so above two parameters will depend on the charge of capacitor

rest we know that capacitance of capacitor is given as

$C = \frac{\epsilon_0 A}{d}$

so it is independent of charge

so correct answer will be

<em>The electric field across the plates. </em>

<em>The potential across the plates.</em>