We/Wm = ge/gm = 120N/1.2N

or

gm = ge/100 = 0.1 m/s^2

density = mass/volume = 3M/(4pir^3)

Re-arranging this equation, we get

M/r^2 = (4/3)×pi×(density)×r

From Newton's universal law of gravitation, the acceleration due to gravity on the moon gm is

gm = G(M/r^2) = G×(4/3)×pi×(density)×r

Solving for density, we get the expression

density = 3gm/(4×pi×G×r)

= 3(0.1)/(4×3.14×6.67×10^-11×2.74×10^6)

= 130.6 kg/m^3

**Answer:**

<h2>0.67 g/mL</h2>

**Explanation:**

The density of a substance can be found by using the formula

m is the mass

v is the volume

From the question

m = 20 g

v = 30 mL

We have

We have the final answer as

<h3>0.67 g/mL</h3>

Hope this helps you

Weight on the Moon = 291 N.

W = g · m, where m stays for the mass and on the Moon g = 1.67 m/s²

291 N = 1.67 m/s² · m

m = 291 kg m / s² : 1.67 m/s²

m = 174.25 kg

Weight on Earth = 9.81 m/s² · 174.25 kg = 1,709.4 N

Answer:

The weight of an astronaut on Earth is **1,709.4 N**.

**Answer:**

See the explanation below

**Explanation:**

No matter at what height a body is dropped, the body will always accelerate to the same reason, which corresponds to Earth's gravitational acceleration.

g = 9.81 [m/s²]

That is, in the first second the velocity is 9.81 [m/s] = 9.81 [m/s²] x 1 [s]

Now in the second 2; 19.62 [m/s²] = 9.81 [m/s²] x 2 [s]

And in the third second 29.43 [m/s²] = 9.81 [m/s²] x 3 [s]

And etc.

**Change in speed = (acceleration) x (time)**

4 minutes = 240 seconds

Change in speed = (40 m/s²) x (240 seconds)

Change in speed = <em>**9,600 m/s**</em>

What you're actually describing here is a car pulling 4 G's for 4 minutes, and ending up going 21,475 miles per hour.

The driver would definitely NOT get a speeding ticket, because nobody could catch him.

Also, his car would heat up and shoot flames from atmospheric friction.

(He could avoid this with some fancy steering, leave the atmosphere, and end up in low-Earth-orbit.)

Actually, I hope there's nobody in the car. His experience wouldn't be pretty.