Answer:
Cost of one daylily = $9
Cost of one pot of ivy = $7
Step-by-step explanation:
Let,
x be the cost of each daylily
y be the cost of each ivy
According to given statement;
14x+7y=161 Eqn 1
2x+14y=88 Eqn 2
Multiplying Eqn 1 by 2
2(14x+7y=161)
28x+14y=322 Eqn 3
Subtracting Eqn 2 from Eqn 3
(28x+14y)-(2x+14y)=322-88
28x+14y-2x-14y=234
26x=234
Dividing both sides by 26

Putting x=9 in Eqn 1
14(9) + 7y = 161
126 + 7y = 161
7y = 161 - 126
7y = 35
Dividing both sides by 7

Hence,
Cost of one daylily = $9
Cost of one pot of ivy = $7
Answer:
Smaller no. = 21
Larger no. = 85
Step-by-step explanation:
Smaller no. = y
Larger no. = 4y + 1
y + (4y + 1) = 106
y + 4y + 1 = 106
5y + 1 = 106
5y = 106 - 1
5y = 105
y = 105/5
y = 21
Smaller no. = y = 21
Larger no. = 4y + 1 = 4×21 + 1 = 84 + 1 = 85
Subtract $7.08 from $166.30 = $159.22
Answer:
A = bh
A = 15 x 6
A = 90 square units
sin90° = hypotenuse/opposite
hypotenuse = sin90° x opposite
hypotenuse = sin90 x 6
h = 5.36
Perimeter = 2a + 2b
= 2 (5.36) + 2 (15)
= 10.72 + 30
= 40.72
It is graph w because it starts at a price of 40 and goes up by 20 every hour.