**Answer:**

**We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.**

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).

Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).

Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).

Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

**Step-by-step explanation:**

# need help or answers answered within minutes/secs hit me up and I got you!

#brainliest

:) <3

-I will also put it in spanish if you need it(Si quieres esta en espanol yo si sabes)