**Answer:**

**Step-by-step explanation:**

Given (64 y Superscript 100 Baseline) Superscript one-half.

Let us write it into an equation.

Apply radical rule: and

Hence, is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.

<h3>Answer:

</h3>

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Explanation:

The instructions don't mention it, but I'm assuming that the height of 4 feet is the max height the of the ball.

If so, then this is the vertex of the parabola.

The ball is on the ground when x = 0 and x = 10. The x coordinate of the vertex is the midpoint of those two roots. So it's at x = 5.

Overall, the vertex is (h,k) = (5,4)

The equation

y = a(x-h)^2 + k

becomes

y = a(x-5)^2 + 4

Next, we plug in the root (x,y) = (10,0) since the ball hits the ground when x = 10. Let's solve for 'a'

y = a(x-5)^2 + 4

0 = a(10-5)^2 + 4

0 = 25a + 4

25a = -4

a = -4/25

We could have used (x,y) = (0,0) and we'd end up with the same 'a' value.

Therefore, the height function is

**Answer:**

**It is given that red dot is about halfway between 12 and 13.**

Draw a number line.Mark points on it on as 1,2,3,.....12,13,...20.

Label 12 as point M and label 13 as N.

Mid point of MN=

=25/2

=12.5

Mark 12.5 as T.

MT =NT

The Red dot is at point N at a distance of 12.5 units from the origin.

Yes. Parenthesis first, then if any exponents, then multiplication or division, then addition and subtraction. PEMDAS.

<u>**Given**</u>:

Line segment DM with end points D(-4,5) and M(6,0) is reflected about the x - axis to give line segment D'M'.

We need to determine the coordinates of the point D'.

<u>**Coordinates of the point D':**</u>

The general to reflect the coordinates over the x - axis is given by

To determine the coordinates of the point D', let us substitute the coordinates of the point D in the above rule.

Thus, we get;

The reflection of the coordinate D(-4,5) about the x - axis to give the point D' is (-4,-5)

Thus, the **coordinates of the point D' is (-4,-5)**