The volume of a cone is described as πr²*⅓h. The radius (r) of the cone is 4 in, and the height (h) is 10 in. So when you plug the numbers in you have 16π*10/3, which, when multiplied out, gives a volume of 167.55 in³.

**Answer: OPTION C**

**Step-by-step explanation:**

** **There are some transformations for a function f(x). Some of them are shown below:

1. If , the function is shifted up "k" units.

2. If , the function is shifted down "k" units.

3. If , the function is shifted left "k" units.

4. If , the function is shifted right "k" units.

In this case you know that the function "g" is the transformation of the function "f".

Observe that the function "f" intersects the y-axis at:

And the function "g" intersects the y-axis at:

Therefore, since both functions are 4 units apart, you can conclude that the function "f" was shifted down 4 units to get the function "g".

Then, the rule that shows that transformation is:

First, you separate the h variable by subtracting s^2 on both sides of the equation, getting

V - s^2 = sh/2

Then, all you have to do is divide both sides by s/2, so you get

h = 2*(v - s^2)/s as your final answer.

Pemdas helps so first you do Parentheses Exponet multiply divide add and subtract

**Answer:**

6.39

**Step-by-step explanation:**

6.39