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Valentin [98]
1 year ago
6

A round hole has a diameter of 2 inches. You have a square peg with sides of 1-1/2 inches. Will the square peg fit into the roun

d hole? Explain please
Mathematics
1 answer:
Ivanshal [37]1 year ago
4 0
In order for a square to fit in a circle, the diagonal of the square
can't be greater than the diameter of the circle.

The diagonal of any square is (length of side) times √2 .
The diagonal of THIS square is (1.5) x (√2) = 2.12 inches.
The diameter of the hole is 2 inches.
The peg will not fit into it.
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REALLY NEED HELP ASAP!!!!!!!
stich3 [128]

Answer: OPTION C

Step-by-step explanation:

There are some transformations for a function f(x). Some of them are shown below:

1. If f(x)+k, the function is shifted up "k" units.

2. If f(x)-k, the function is shifted down "k" units.

3. If f(x+k), the function is shifted left "k" units.

4. If f(x-k), the function is shifted right "k" units.

In this case you know that the function "g" is the transformation of the function "f".

Observe that the function "f" intersects the y-axis at:

y=2

And the function "g" intersects the y-axis at:

y=-2

Therefore, since both functions are 4 units apart, you can conclude that the function "f" was shifted down 4 units to get the function "g".

Then, the rule that shows that transformation is:

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5 0
1 year ago
V=s^2+1/2sh solve for h
wariber [46]
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How do you solve this?
motikmotik
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