You're driving down the highway late one night at 20 m/s when a deer steps onto the road 49 m in front of you. You reaction time
before stepping on the brakes is 0.50 s, and the maximum deceleration of your car is 10m/s2. a. How much distance is between you and the deer when you come to a stop?
b. What is the maximum speed you could have and still not hit the deer?
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions. x = distance from tree to fox = 8.0 m <span>x1 = distance from tree to where carrion falls </span> <span>x2 = distance from where carrion falls to fox </span> <span>x1 + x2 = x </span> <span>vix = 1.3 m/s </span>
The work done in bringing two charges q₁ and q₂ separated by a distance, r together is W = kq₁q₂/r. With the first charge q₁ in place, the work done in bringing the second charge into the vertex of the equilateral at a distance, r is W₁₂ = kq₁q₂/r. Since the first and second charges are in place, the work done in bringing the third charge q₃ in place is work done W₁₃ between q₁ and q₃ = kq₁q₃/r plus work done W₂₃ between q₂ and q₃ = kq₂q₃/r. So the total work done in assembling the atomic nucleus is W = W₁₂ + W₁₃ + W₂₃ = kq₁q₂/r + kq₁q₃/r + kq₂q₃/r. Since q₁ = q₂ = q₃ = q = 1.6 × 10⁻¹⁹ C, W = 3kq²/r. Since r = side of equilateral triangle = 2.0 × 10⁻¹⁵ m. W = 3 × 9 × 10⁹ × (1.6 × 10⁻¹⁹)²/2.0 × 10⁻¹⁵ = 3.456 × 10⁻⁴³ J ≅ 3.46 × 10⁻⁴³ J
Because there is no wind, snow, rain, sleet, blowing dust, hail, or humidity on the moon to smooth them over and fill them in. Without those things, we'd be able to see all the ancient meteor collisions on Earth.