Q5. A solenoid of length 100 cm is wound uniformly with 10 000 turns
1 answer:
Answer:
<em>i) 0.05 T</em>
<em>ii) 0.025 T</em>
Explanation:
current I = 4 A
length of solenoid L = 100 cm = 1 m
number of turns N = 10000 turns
number of turns per unit length n = N/L = 10000/1 = 10000 turns/meter
i) magnetic field on the axis of the solenoid at the center
B = μ
where μ is vacuum permeability = 4π×10−7 H/m = 1.256 x H/m
B = 1.256 x x 10000 x 4 = <em>0.05 T</em>
ii) magnetic field on the axis at the end will be equal to
B = (μ) ÷ 2
<em>this is based on the assumption that the length of the solenoid is far greater than than the diameter of the solenoid</em>. Therefore,
B = 0.05 ÷ 2 = <em>0.025 T</em>
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