I have a 74% in my class and I need a 78% to pass what do I need to get on my final exam?

1 answer:

3 0

So the 74% that you have right now is the other 80% of your grade. So you multiply it by its weight and solve for the other one making it equal to 78%.

(.74)(.8) + (.2)(x) = .78
.592 + (.2)(x) = .78
(.2)(x) = .188
(x) = .94

So, you need to get a 94% on your final test.

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Answer:

508

Step-by-step explanation:

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A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/

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Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

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The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016$