3.3. Just add all the partial pressures together to get the total pressure.
Answer:
-266 kJ
Explanation:
There is some info missing. I think this is the original question.
<em>A mixture of nitrogen and neon gas is expanded from a volume of 53.0 L to a volume of 90.0 L, while the pressure is held constant at 71.0 atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.</em>
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Given data
Initial volume = 53.0 L
Final volume = 90.0 L
Pressure = 71.0 atm
We can find the work (w) associated with the expansion of the gaseous mixture using the following expression.
w = - P × ΔV = - 71.0 atm × (90.0 L - 53.0 L) = -2.63 × 10³ atm . L
w = -2.63 × 10³ atm . L × (101.3 J/ 1 atm . L) = -2.66 × 10⁵ J = -266 kJ
The negative sign means that the system does work on the surroundings.
Answer:
Graham's law states that the rate of effusion or of diffusion of a gas is inversely proportional to the square root of its molecular weight. So, rate of diffusion of hydrogen gas is four times faster than oxygen gas.
Explanation:
Answer:
see explanation
Explanation:
An AX₂E₂ geometry is derived from an AX₄ parent geometry and is based upon 4 regions of electron density about the central element and defines a tetrahedral geometry and the geometry is bent angular.
An example is the water molecule (H₂O) with two covalent O - H bonds and two free pair electrons on the central oxygen element.
Q=mc(delta T)
= (100 g)(1 cal/g(K))(60-40)
=100(20)
=2000 calories
letter C
