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sashaice [31]
1 year ago
13

A bag of 100 tulip bulbs purchased from a nursery contains 20 red tulip​ bulbs, 20 yellow tulip​ bulbs, and 60 purple tulip bulb

s. ​(a) What is the probability that a randomly selected tulip bulb is​ red? ​(b) What is the probability that a randomly selected tulip bulb is​ purple? ​(c) Interpret these two probabilities.
Mathematics
1 answer:
nadezda [96]1 year ago
3 0

Answer: a) 0.2   b) 0.6

c) The event of selecting red tulip is not likely to occur.

The event of selecting purple tulip is likely to occur.

Step-by-step explanation:

Given : Total number of tulips = 100

The number of red tulips = 20

The number of purple tulips =60

The probability that a randomly selected tulip bulb is​ red :-

\dfrac{\text{Number of red tulips}}{\text{Total tulips}}\\\\=\dfrac{20}{100}=0.2

Since 0.2 is less than 0.5.

It means that the event of selecting red tulip is not likely to occur.

The probability that a randomly selected tulip bulb is​ purple :-

\dfrac{\text{Number of purple tulips}}{\text{Total tulips}}\\\\=\dfrac{60}{100}=0.6

Since 0.6 is more than 0.5.

It means that the event of selecting purple tulip is likely to occur.

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1 year ago
Which fraction is in its lowest terms?<br><br> 4/5<br> 3/9<br> 4/6<br> 2/8
artcher [175]

Answer:

4/5

Step-by-step explanation:

  1. 4/5 cannot be simplified
  2. 3/9 = 1/3
  3. 4/6 = 2/3
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6 0
1 year ago
Match each verbal description to its corresponding expression.
Aliun [14]
I need points thank you
7 0
1 year ago
4.
noname [10]

Answer:

(a) Candy's initial sum as a terms of x is $6x

(b) x = $60

(c) $350

Step-by-step explanation:

The given parameters are;

The ratio in which Aliyah, Brenda and Candy share the sum of money = 3:5:6

The amount Candy later gives Aliyah = $100

The amount Candy later gives Brenda = $50

The new ratio of the sum of the shared money between Aliyah, Brenda and Candy = 2:3:3

(a) Whereby Aliyah has $3x at the start, we have;

Total sum of mony = Y

Amount of Aliyah's initial share = Y × 3/(3 + 5 + 6) = Y×3/14

Therefore, Y×3/14 = $3x

x = Y×3/14 ÷ 3 = Y/14

Amount of Candy's initial share = Y × 6/14

Therefore Candy's initial sum as a terms of x = $6x

(b) Given that Aliyah's and Candy's initial sum as a function of x are   $3x and $6x, therefore, in the ratio 3:5:6, Brenda's  initial sum as a function of x = $5x

Which gives;

Total amount of money = $14x

With

6x - 150, 3x + 100, and 5x + 50, the ratio =is 2:3:3

Therefore, we have;

14·x × 2/(2 + 3 + 3) = (6·x - 150)

14·x × 2/(8) = (6·x - 150)

14·x × 1/4 = (6·x - 150)

7·x/2 = (6·x - 150)

12·x - 300 = 7·x

12·x - 7·x = 300

5·x = 300

x = $60

(b) The final amount of money with Brenda = 5x + 50 = 5 × 60 + 50 = $350

The final amount of money with Brenda = $350.

8 0
1 year ago
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