1 year ago

Can some one help me with this??? Really need help

Mathematics

2 answers:

Vitek1552 [10]1 year ago

6 0

$1-\frac{1}{3}-\frac{3}{7}=\\
\frac{21}{21}-\frac{7}{21}-\frac{9}{21}=\\
\frac{5}{21}$

mamaluj [8]1 year ago

6 0

Let the complete circle be signified as = 1
Shaded region will be equal to = total - 2 unshared part
= 1 - 1/3 - 3/7
taking LCM
= (21 - 7 - 9)/21
= 5/21

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If an open box has a square base and a volume of 115 in.3 and is constructed from a tin sheet, find the dimensions of the box, a

Karolina [17]

Let h = height of the box,
x = side length of the base.

Volume of the box is $V=x^{2} h = 115$ .
So $h = \frac{115}{ x^{2} }$

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
$S = 2( x^{2} + hx + hx) \\ = 2 x^{2} + 4hx \\ = 2 x^{2} + 4( \frac{115}{ x^{2} } )x$
$= 2 x^{2} + \frac{460}{x}$
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

$S' = 4x- \frac{460}{ x^{2} } = 0$
$4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86$
Then $h= \frac{115}{4.86^{2}} = 4.87$
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5 0

1 year ago

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LekaFEV [45]

Answer:

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Step-by-step explanation:

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