What is your displacement if you walk 80 m north, 15 m east, 20 m south, 35 m west, and then 60 m south?

Explanation:

This is due to the relative position of the moon to an observer on the surface of the earth. Due to this relative position, the side of the moon facing the earth and the sun and reflecting the beam back to earth will differ to different observers in different locations.

During a full moon, the whole side of the moon that is facing the earth (remember this is relative to the observer on the earth’s surface) is being lit by the sun. As the moon changes position as it revolves around the earth, the proportion of this side lit by the sun will decrease from a full moon until the section is no longer being shone by the sun hence forming a new moon,  

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I shall assume the following equations are the ones of interest as none was provided:

(a) 63 Li + 56 28Ni →?

(b) 40 20Ca + 248 96Cm→147 62Sm + ?

(c) 88 38Sr + 84 36Kr→116 46Pd + ?

(d) 40 20Ca + 238 92U→70 30Zn + 4 10 n + 2?

I shall also assume in the following calculations that the mass number of the unknown products is 'a' and the atomic number of the unknown products is 'b'.

In balancing nuclear equations, we observe the following rules:

I. The total number of protons and neutrons in the products and reactants must be the same ( conservation of mass number, A ).

II. The total number of nuclear charges in the products and reactants must be the same ( conservation of atomic number, Z ).

For (a),

63 Li + 56 28Ni→?

Add mass number, A, of reactants = 6+56 = 62

Add atomic number, Z, of reactants = 3+28 = 31

A of reactants = A of unknown product = 62

and, Z of reactants = Z of unknown product = 31

Hence, unknown product is the element with Z as 31 = Ga

Balanced equation becomes:

63 Li + 56 28Ni → 62 31Ga

For (b),

40 20Ca + 248 96Cm→147 62Sm + ?

A of reactants = 40+248 = 288

A of products = 147 + 'a'

But A of reactants = A of products

288 = 147 + 'a'

‘a’ = 288 – 147 = 141

Also,

Z of reactants = 20 + 96 = 116

Z of products = 62 + 'b'

Z of reactants = Z of products

116 = 62 + 'b'

'b' = 116 – 62 = 54

So, unknown product is the element with Z = 54 = Xe

Balanced equation is:

40 20Ca + 248 96Cm→147 62Sm + 141 54Xe

For (c),

88 38Sr + 84 36Kr→116 46Pd + ?

A of reactants = 88 + 84 = 172

A of products = 116 + 'a'

But A of reactants = A of products

172 = 116 + 'a'

‘a’ = 172 – 116 = 56

Also,

Z of reactants = 38 + 36 = 74

Z of products = 46 + 'b'

Z of reactants = Z of products

74 = 46 + 'b'

'b' = 74 – 46 = 28

So, unknown product is the element with Z = 28 = Ni

Balanced equation is:

88 38Sr + 84 36Kr→116 46Pd + 56 28Ni

For (d),

40 20Ca + 238 92U→70 30Zn + 4 10 n + 2?

A of reactants = 40 + 238 = 278

A of products = 70 + (4 x 1) + (2 x 'a') = 70 + 4 + 2a = 74 + 2a

But, A of reactants = A of products

278 = 74 + 2a

2a = 278 – 74

2a = 204

'a' = 204/2 = 102

Also,

Z of reactants = 20 + 92 = 112

Z of products = 30 + (4 x 0) + (2 x b) = 30 + 0 + 2b = 30 + 2b

Z of reactants = Z of products

112 = 30 + 2b

2b = 112 – 30

2b = 82

‘b’ = 82/2 = 41

Therefore, unknown product is element with Z = 41 =Nb

Balanced equation is:

40 20Ca + 238 92U→70 30Zn + 4 10 n + 2 102 41Nb

Givens

m = 2.26 g

c = 4.19 J/(g * oC)

Δt = 23.5oC - 0 = 23.5oC

hf = heat of fusion for ice = 334 J/g

Equation

H = m*c*Δt +  hf * m

H = m*(c*Δt + hf)

Solution

H = 2.26 * (4.19 * 23.5  + 334)

H = 2.26 * (432.5)

H = 977.4 J

Answer:

yes

Explanation:

<em>pp popo</em>

Answer:

a) 600 J

b) 75 W

Explanation:

Force= 400 N, distance = 150 cm = 1.5 m, time= 8s

a) Work is the product of force acting on an object and distance (or displacement). The S.I unit of work is the joules.

Work = force × distance = 400 × 1.5 = 600 J

b) Power is the amount of energy transferred per unit time. It is the ratio of work to time. The S.I unit of power is watt

Power = work/time = 600 / 8 = 75 W