Let a, b, and c represent the running times of persons a, b, and c, respectively.

The problem statement describes several relationships:

... a + b + c = 66 . . . . . their combined time is 66 minutes

... b = 2 + 5a . . . . . . . . b's time is 2 minutes more than 5 times a's

... 2b + 4a = c . . . . . . . twice b's time plus 4 times a's time is equal to c's

These can be solved a variety of ways. One way is to use the second equation for b to substitute into the other equations. This gives ...

... a + (2+5a) + c = 66

... 2(2+5a) +4a = c

The first of these simplifies to

... 6a +c = 64

The second of these simplifies to

... 9a -c = -4

Adding these two equations together gives

... 15a = 60

... a = 4 . . . . . . . divide by 15

From above, b = 2 + 5a = 2 + 5·4 = 22

**It took b 22 minutes to run that part of the race.**