Answer: b. 10/3
Average = Sum of all values/ Total number of value
= 9 + 12 + 7 + 11 + 8/ 5 (as there are 5 numbers, which are 9, 12, 7, 11 and 8)
= 47/5 = 9.4
So the average is 9.4
Hope you understood!!
Each input should have one output.
Let a, b, and c represent the running times of persons a, b, and c, respectively.
The problem statement describes several relationships:
... a + b + c = 66 . . . . . their combined time is 66 minutes
... b = 2 + 5a . . . . . . . . b's time is 2 minutes more than 5 times a's
... 2b + 4a = c . . . . . . . twice b's time plus 4 times a's time is equal to c's
These can be solved a variety of ways. One way is to use the second equation for b to substitute into the other equations. This gives ...
... a + (2+5a) + c = 66
... 2(2+5a) +4a = c
The first of these simplifies to
... 6a +c = 64
The second of these simplifies to
... 9a -c = -4
Adding these two equations together gives
... 15a = 60
... a = 4 . . . . . . . divide by 15
From above, b = 2 + 5a = 2 + 5·4 = 22
It took b 22 minutes to run that part of the race.
put D I got it right when I put it there;)
We need to figure out how many bats were produced.
First let's write the equation. Cost is $28 for each bat, and we start with fixed expenses of $58,780
y=28x + 58780
We are given y, total expenses at 406,960
so 406,960 = 28x + 58780
subtract 58780 from both sides
406,960 - 58,780 = 28x
348,180 = 28x
divide both sides by 28
12,435 = x
This means they produced 12,435 bats.
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